2x^2+14x-25.5=0

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Solution for 2x^2+14x-25.5=0 equation: 



2x^2+14x-25.5=0

a = 2; b = 14; c = -25.5;
Δ = b2-4ac
Δ = 142-4·2·(-25.5)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-20}{2*2}=\frac{-34}{4}
=-8+1/2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+20}{2*2}=\frac{6}{4}
=1+1/2
$

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